Самый простой способ чтения / записи содержимого файла в Python

UPDATE!

Лучшая альтернатива, также созданная мной, находится здесь: https://stackoverflow.com/a/23692008/2829600 (поддерживает «функции удаления»)

ORIGINAL POST:

Я написал эту простую функцию для обработки задержки выполнения, полезной внутри jQuery .scroll () и .resize () Таким образом, callback_f будет запускаться только один раз для определенной строки идентификатора.

function delay_exec( id, wait_time, callback_f ){

    // IF WAIT TIME IS NOT ENTERED IN FUNCTION CALL,
    // SET IT TO DEFAULT VALUE: 0.5 SECOND
    if( typeof wait_time === "undefined" )
        wait_time = 500;

    // CREATE GLOBAL ARRAY(IF ITS NOT ALREADY CREATED)
    // WHERE WE STORE CURRENTLY RUNNING setTimeout() FUNCTION FOR THIS ID
    if( typeof window['delay_exec'] === "undefined" )
        window['delay_exec'] = [];

    // RESET CURRENTLY RUNNING setTimeout() FUNCTION FOR THIS ID,
    // SO IN THAT WAY WE ARE SURE THAT callback_f WILL RUN ONLY ONE TIME
    // ( ON LATEST CALL ON delay_exec FUNCTION WITH SAME ID  )
    if( typeof window['delay_exec'][id] !== "undefined" )
        clearTimeout( window['delay_exec'][id] );

    // SET NEW TIMEOUT AND EXECUTE callback_f WHEN wait_time EXPIRES,
    // BUT ONLY IF THERE ISNT ANY MORE FUTURE CALLS ( IN wait_time PERIOD )
    // TO delay_exec FUNCTION WITH SAME ID AS CURRENT ONE
    window['delay_exec'][id] = setTimeout( callback_f , wait_time );
}


// USAGE

jQuery(window).resize(function() {

    delay_exec('test1', 1000, function(){
        console.log('1st call to delay "test1" successfully executed!');
    });

    delay_exec('test1', 1000, function(){
        console.log('2nd call to delay "test1" successfully executed!');
    });

    delay_exec('test1', 1000, function(){
        console.log('3rd call to delay "test1" successfully executed!');
    });

    delay_exec('test2', 1000, function(){
        console.log('1st call to delay "test2" successfully executed!');
    });

    delay_exec('test3', 1000, function(){
        console.log('1st call to delay "test3" successfully executed!');
    });

});

/* RESULT
3rd call to delay "test1" successfully executed!
1st call to delay "test2" successfully executed!
1st call to delay "test3" successfully executed!
*/
66
задан Michael 5 July 2019 в 09:49
поделиться