Есть ли двоичный эквивалент Системы. Текст. StringBuilder?

Example

Я знаю, что очень опоздал на эту вечеринку, но я написал более сложную функцию для генерации набора контрастных случайных цветов для другого проект. Они оба (по крайней мере, несколько) привлекательны и действительно случайны (не основаны на предопределенных цветах), но мой код немного сложнее, чем некоторые другие ответы (так что это не просто для получения основ)

Это предназначен для пользователей, которые хотят иметь более одного случайного цвета на своей странице и хотят убедиться, что никакие два цвета не слишком похожи.

Fiddle

var generateRandomColors=function(number){
/*
This generates colors using the following algorithm:
Each time you create a color:
    Create a random, but attractive, color{
        Red, Green, and Blue are set to random luminosity.
        One random value is reduced significantly to prevent grayscale.
        Another is increased by a random amount up to 100%.
        They are mapped to a random total luminosity in a medium-high range (bright but not white).
    }
    Check for similarity to other colors{
        Check if the colors are very close together in value.
        Check if the colors are of similar hue and saturation.
        Check if the colors are of similar luminosity.
        If the random color is too similar to another,
        and there is still a good opportunity to change it:
            Change the hue of the random color and try again.
    }
    Output array of all colors generated
*/
    //if we've passed preloaded colors and they're in hex format
    if(typeof(arguments[1])!='undefined'&&arguments[1].constructor==Array&&arguments[1][0]&&arguments[1][0].constructor!=Array){
        for(var i=0;i360){ //if it's too high
                hsl[0]-=360 //decrease it mod 360
            }else if(hsl[0]<0){ //if it's too low
                hsl[0]+=360 //increase it mod 360
            }
            return hslToRGB(hsl); //convert back to rgb
        },differenceRecursions={//stores recursion data, so if all else fails we can use one of the hues already generated
            differences:[],//used to calculate the most distant hue
            values:[]//used to store the actual colors
        },fixDifference=function(color){//recursively asserts that the current color is distinctive
            if(differenceRecursions.values.length>23){//first, check if this is the 25th recursion or higher. (can we try any more unique hues?)
                //if so, get the biggest value in differences that we have and its corresponding value
                var ret=differenceRecursions.values[differenceRecursions.differences.indexOf(Math.max.apply(null,differenceRecursions.differences))];
                differenceRecursions={differences:[],values:[]}; //then reset the recursions array, because we're done now
                return ret; //and then return up the recursion chain
            } //okay, so we still have some hues to try.
            var differences=[]; //an array of the "difference" numbers we're going to generate.
            for(var i=0;i1){ //if there's a problem with range or luminosity
                    //set the biggest difference for these colors to be whatever is most significant
                    differences.push(Math.min(differenceRange+lumDifference,sumDifference));
                }
                differences.push(sumDifference); //otherwise output the raw difference in RGB values
            }
            var breakdownAt=64, //if you're generating this many colors or more, don't try so hard to make unique hues, because you might fail.
            breakdownFactor=25, //how much should additional colors decrease the acceptable difference
            shiftByDegrees=15, //how many degrees of hue should we iterate through if this fails
            acceptableDifference=250, //how much difference is unacceptable between colors
            breakVal=loadedColors.length/number*(number-breakdownAt), //break down progressively (if it's the second color, you can still make it a unique hue)
            totalDifference=Math.min.apply(null,differences); //get the color closest to the current color
            if(totalDifference>acceptableDifference-(breakVal<0?0:breakVal)*breakdownFactor){ //if the current color is acceptable
                differenceRecursions={differences:[],values:[]} //reset the recursions object, because we're done
                return color; //and return that color
            } //otherwise the current color is too much like another
            //start by adding this recursion's data into the recursions object
            differenceRecursions.differences.push(totalDifference);
            differenceRecursions.values.push(color);
            color=shiftHue(color,shiftByDegrees); //then increment the color's hue
            return fixDifference(color); //and try again
        },color=function(){ //generate a random color
            var scale=function(x){ //maps [0,1] to [300,510]
                return x*210+300 //(no brighter than #ff0 or #0ff or #f0f, but still pretty bright)
            },randVal=function(){ //random value between 300 and 510
                return Math.floor(scale(Math.random()))
            },luminosity=randVal(), //random luminosity
                red=randVal(), //random color values
                green=randVal(), //these could be any random integer but we'll use the same function as for luminosity
                blue=randVal(),
                rescale, //we'll define this later
                thisColor=[red,green,blue], //an array of the random values
                /*
                #ff0 and #9e0 are not the same colors, but they are on the same range of the spectrum, namely without blue.
                Try to choose colors such that consecutive colors are on different ranges of the spectrum.
                This shouldn't always happen, but it should happen more often then not.
                Using a factor of 2.3, we'll only get the same range of spectrum 15% of the time.
                */
                valueToReduce=Math.floor(lastLoadedReduction+1+Math.random()*2.3)%3, //which value to reduce
                /*
                Because 300 and 510 are fairly close in reference to zero,
                increase one of the remaining values by some arbitrary percent betweeen 0% and 100%,
                so that our remaining two values can be somewhat different.
                */
                valueToIncrease=Math.floor(valueToIncrease+1+Math.random()*2)%3, //which value to increase (not the one we reduced)
                increaseBy=Math.random()+1; //how much to increase it by
            lastLoadedReduction=valueToReduce; //next time we make a color, try not to reduce the same one
            thisColor[valueToReduce]=Math.floor(thisColor[valueToReduce]/16); //reduce one of the values
            thisColor[valueToIncrease]=Math.ceil(thisColor[valueToIncrease]*increaseBy) //increase one of the values
            rescale=function(x){ //now, rescale the random numbers so that our output color has the luminosity we want
                return x*luminosity/thisColor.reduce(function(a,b){return a+b}) //sum red, green, and blue to get the total luminosity
            };
            thisColor=fixDifference(thisColor.map(function(a){return rescale(a)})); //fix the hue so that our color is recognizable
            if(Math.max.apply(null,thisColor)>255){ //if any values are too large
                rescale=function(x){ //rescale the numbers to legitimate hex values
                    return x*255/Math.max.apply(null,thisColor)
                }
                thisColor=thisColor.map(function(a){return rescale(a)});
            }
            return thisColor;
        };
    for(var i=loadedColors.length;i

Обратите внимание, хотя я не делаю этого в моем примере, это также может быть использовано для добавления новых отдельных, случайных цветов в набор:

generateRandomColors(1,generateRandomColors(10))

10
задан kdt 24 May 2009 в 13:35
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2 ответа

I don't think there is an exact equivalent, but you could get it done with a BinaryWriter:

http://msdn2.microsoft.com/en-us/library/system.io.binarywriter.aspx

MemoryStream m = new MemoryStream();
BinaryWriter writer = new BinaryWriter(m);
writer.Write(true);
writer.Write("hello");
writer.Write(12345);
writer.Flush();
return m.ToArray();
21
ответ дан 3 December 2019 в 18:01
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Запишите их в MemoryStream, возможно, используя StreamWriter / BinaryWriter. Если порядок байтов является проблемой, некоторые из классов здесь могут помочь

1
ответ дан 3 December 2019 в 18:01
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