Я нашел, что он отлично работает, используя display: block; на изображении и вертикально-выровнять: верх; на текст.
.imagebox {
width:200px;
float:left;
height:88px;
position:relative;
background-color: #999;
}
.container {
width:600px;
height:176px;
background-color: #666;
position:relative;
overflow:hidden;
}
.text {
color: #000;
font-size: 11px;
font-family: robotomeduim, sans-serif;
vertical-align:top;
}
.imagebox img{ display:block;}
Image title
Image title
Image title
Image title
Image title
Image title
или вы можете отредактировать код a JS FIDDLE
Непосредственно покинуть страницу mysqli: http://php.net/manual/en/mysqli.commit.php
<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
/* set autocommit to off */
$mysqli->autocommit(FALSE);
/* Insert some values */
$mysqli->query("INSERT INTO table1 VALUES ('DEU', 'Bavarian', 'F', 11.2)");
$mysqli->query("INSERT INTO table2 VALUES ('DEU', 'Bavarian', 'F', 11.2)");
/* commit transaction */
$mysqli->commit();
/* close connection */
$mysqli->close();
* Редактировать с помощью подготовленных операторов для " non-sane ":
<?php
$mysqli = new mysqli("localhost", "root", "", "");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
/* set autocommit to off */
$mysqli->autocommit(FALSE);
$stmt1 = $mysqli->prepare("INSERT INTO tbl1 (id, intro) VALUES (?, ?)");
$stmt2 = $mysqli->prepare("INSERT INTO tbl2 (id, name) VALUES (?, ?)");
$str1 = 'abc';
$str2 = 'efg';
$str3 = 'hij';
$str4 = 'klm';
$stmt1->bind_param('ss', $str1, $str2);
$stmt2->bind_param('ss', $str3,$str4);
if ($stmt1->execute() == false)
{
echo 'First query failed: ' . $mysqli->error;
}
$stmt1->close();
if ($stmt2->execute() == false)
{
echo 'Second query failed: ' . $mysqli->error;
}
$stmt2->close();
$mysqli->close();