HTML-таблица: сохраните ту же ширину для столбцов

Мои 2 цента:

CREATE TABLE #tmp
(
  [Id] BIGINT IDENTITY(1, 1) PRIMARY KEY CLUSTERED,
  [Task] INT,
  [SubTask] INT,
  [User] NCHAR(1),
  [Group] NVARCHAR(32)
)

INSERT INTO #tmp ([Task], [SubTask], [User], [Group]) VALUES (1234, 9999, 'A', 'Team');
INSERT INTO #tmp ([Task], [SubTask], [User], [Group]) VALUES (1234, 9998, 'B', 'Team');
INSERT INTO #tmp ([Task], [SubTask], [User], [Group]) VALUES (1234, 9997, 'C', 'Team');
INSERT INTO #tmp ([Task], [SubTask], [User], [Group]) VALUES (2345, 6666, 'A', 'Team');
INSERT INTO #tmp ([Task], [SubTask], [User], [Group]) VALUES (2345, 6665, 'B', 'Team');
INSERT INTO #tmp ([Task], [SubTask], [User], [Group]) VALUES (3456, 5555, 'A', 'Individual A');
INSERT INTO #tmp ([Task], [SubTask], [User], [Group]) VALUES (4567, 4444, 'B', 'Individual B');
INSERT INTO #tmp ([Task], [SubTask], [User], [Group]) VALUES (5678, 3333, 'C', 'Individual C');

SELECT          [A].[Task],
                [B].[SubTask],
                [B].[User],
                CASE [A].[Cnt]
                WHEN 1 THEN 'Individual ' + [User]
                ELSE 'Team'
                END AS [GroupCalculated],
                [Group],
                [A].[Cnt]

FROM (          SELECT          [Task],
                                COUNT(*) AS [Cnt]
                FROM            #tmp
                GROUP BY        [Task]) AS [A]

INNER JOIN      #Tmp AS [B]
    ON          [B].[Task] = [A].[Task];

DROP TABLE #tmp;