А вот и последняя запись4: немного очистил ваш код, это должно помочь вам начать. https://codepen.io/anon/pen/xmeWBO?editors=1100
.container{
margin-left:20px;
display:flex;
flex-direction: row;
}
.logo{
width: auto;
fill:orange;
height: 57px;
}
a {
text-decoration: none;
color: inherit;
}
ul {
list-style: none;
display: flex;
flex-grow: 1;
}
ul li {
padding: 1rem
}
.svg-container {
display: flex;
}
.svg-container svg {
height: 20px;
padding: 1.8rem 1rem;
}
Here's another option that is more optimized where you pass in your allocated buffer. Make sure it's the correct size.
// buffer must have length >= sizeof(int) + 1
// Write to the buffer backwards so that the binary representation
// is in the correct order i.e. the LSB is on the far right
// instead of the far left of the printed string
char *int2bin(int a, char *buffer, int buf_size) {
buffer += (buf_size - 1);
for (int i = 31; i >= 0; i--) {
*buffer-- = (a & 1) + '0';
a >>= 1;
}
return buffer;
}
#define BUF_SIZE 33
int main() {
char buffer[BUF_SIZE];
buffer[BUF_SIZE - 1] = '\0';
int2bin(0xFF000000, buffer, BUF_SIZE - 1);
printf("a = %s", buffer);
}
Пара вещей:
int f = 32;
int i = 1;
do{
str[--f] = i^a?'1':'0';
}while(i<<1);
#include<stdio.h>
//#include<conio.h> // use this if you are running your code in visual c++, linux don't
// have this library. i have used it for getch() to hold the screen for input char.
void showbits(int);
int main()
{
int no;
printf("\nEnter number to convert in binary\n");
scanf("%d",&no);
showbits(no);
// getch(); // used to hold screen...
// keep code as it is if using gcc. if using windows uncomment #include & getch()
return 0;
}
void showbits(int n)
{
int i,k,andmask;
for(i=15;i>=0;i--)
{
andmask = 1 << i;
k = n & andmask;
k == 0 ? printf("0") : printf("1");
}
}
Вот простой алгоритм.
void decimalToBinary (int num) {
//Initialize mask
unsigned int mask = 0x80000000;
size_t bits = sizeof(num) * CHAR_BIT;
for (int count = 0 ;count < bits; count++) {
//print
(mask & num ) ? cout <<"1" : cout <<"0";
//shift one to the right
mask = mask >> 1;
}
}
Несколько предложений:
malloc()
malloc()
Вот код:
#include <stdlib.h>
#include <limits.h>
char * int2bin(int i)
{
size_t bits = sizeof(int) * CHAR_BIT;
char * str = malloc(bits + 1);
if(!str) return NULL;
str[bits] = 0;
// type punning because signed shift is implementation-defined
unsigned u = *(unsigned *)&i;
for(; bits--; u >>= 1)
str[bits] = u & 1 ? '1' : '0';
return str;
}
Две вещи:
'\ 0'
. while (a> 0)
сразу будет ложным. В сторону: внутренняя функция malloc уродлива. А как насчет предоставления буфера для int2bin?
Your string isn't null-terminated. Make sure you add a '\0'
character at the end of the string; or, you could allocate it with calloc
instead of malloc
, which will zero the memory that is returned to you.
By the way, there are other problems with this code:
free()
ing the allocated string. You'll leak memory if you just call it in a printf
call.Here's an alternative implementation you could use.
#include <stdlib.h>
#include <limits.h>
char *int2bin(unsigned n, char *buf)
{
#define BITS (sizeof(n) * CHAR_BIT)
static char static_buf[BITS + 1];
int i;
if (buf == NULL)
buf = static_buf;
for (i = BITS - 1; i >= 0; --i) {
buf[i] = (n & 1) ? '1' : '0';
n >>= 1;
}
buf[BITS] = '\0';
return buf;
#undef BITS
}
Usage:
printf("%s\n", int2bin(0xFF00000000, NULL));
The second parameter is a pointer to a buffer you want to store the result string in. If you don't have a buffer you can pass NULL
and int2bin
will write to a static
buffer and return that to you. The advantage of this over the original implementation is that the caller doesn't have to worry about free()
ing the string that gets returned.
A downside is that there's only one static buffer so subsequent calls will overwrite the results from previous calls. You couldn't save the results from multiple calls for later use. Also, it is not threadsafe, meaning if you call the function this way from different threads they could clobber each other's strings. If that's a possibility you'll need to pass in your own buffer instead of passing NULL
, like so:
char str[33];
int2bin(0xDEADBEEF, str);
puts(str);
Two simple versions coded here (reproduced with mild reformatting).
#include <stdio.h>
/* Print n as a binary number */
void printbitssimple(int n)
{
unsigned int i;
i = 1<<(sizeof(n) * 8 - 1);
while (i > 0)
{
if (n & i)
printf("1");
else
printf("0");
i >>= 1;
}
}
/* Print n as a binary number */
void printbits(int n)
{
unsigned int i, step;
if (0 == n) /* For simplicity's sake, I treat 0 as a special case*/
{
printf("0000");
return;
}
i = 1<<(sizeof(n) * 8 - 1);
step = -1; /* Only print the relevant digits */
step >>= 4; /* In groups of 4 */
while (step >= n)
{
i >>= 4;
step >>= 4;
}
/* At this point, i is the smallest power of two larger or equal to n */
while (i > 0)
{
if (n & i)
printf("1");
else
printf("0");
i >>= 1;
}
}
int main(int argc, char *argv[])
{
int i;
for (i = 0; i < 32; ++i)
{
printf("%d = ", i);
//printbitssimple(i);
printbits(i);
printf("\n");
}
return 0;
}