Преобразование строки даты и времени в миллисекунды:
public static final String DATE_TIME_FORMAT = "MM/dd/yyyy HH:mm:ss a";
или
public static final String DATE_TIME_FORMAT = "yyyy-MM-dd'T'HH:mm:ss";
или
public static final String DEFAULT_DATE_TIME_FORMAT = "yyyy-MM-dd'T'HH:mm:ssZZZZZ";
//TimeZone.getAvailableIds() to list all timezone ids
String timeZone = "EST5EDT";//it can be anything timezone like IST, GMT.
String time = "2/21/2018 7:41:00 AM";
public static long[] convertTimeInMillis(String dateTimeFormat, String timeZone, String... times) throws ParseException {
SimpleDateFormat dateFormat = new SimpleDateFormat(dateTimeFormat, Locale.getDefault());
dateFormat.setTimeZone(TimeZone.getTimeZone(timeZone));
long[] ret = new long[times.length];
for (int i = 0; i < times.length; i++) {
String timeWithTZ = times[i] + " "+timeZone;
Date d = dateFormat.parse(timeWithTZ);
ret[i] = d.getTime();
}
return ret;
}
// миллисекунд до dateString
public static String convertTimeInMillisToDateString(long timeInMillis, String DATE_TIME_FORMAT) {
Date d = new Date(timeInMillis);
SimpleDateFormat sdf = new SimpleDateFormat(dateFormat);
return sdf.format(d);
}
Попробуйте следующее:
writer.WriteStartElement("AmazonEnvelope");
writer.WriteAttributeString(
"xmlns", "xsi", null, "http://www.w3.org/2001/XMLSchema-instance");
writer.WriteAttributeString(
"xsi", "noNamespaceSchemaLocation", null, "amzn-envelope.xsd");
...
writer.WriteEndElement();
Является ли .NET 3.5 вариантом?
XNamespace ns = "http://www.w3.org/2001/XMLSchema-instance";
string s = new XElement("AmazonEnvelope",
new XAttribute(XNamespace.Xmlns + "xsi", ns),
new XAttribute(ns + "noNamespaceSchemaLocation", "amzn-envelope.xsd")
).ToString();
или с XmlWriter
:
const string ns = "http://www.w3.org/2001/XMLSchema-instance";
writer.WriteStartDocument();
writer.WriteStartElement("AmazonEnvelope");
writer.WriteAttributeString("xmlns", "xsi", "", ns);
writer.WriteAttributeString("xsi", "noNamespaceSchemaLocation",
ns, "mzn-envelope.xsd");
writer.WriteEndDocument();