Python - Подпроцесс - Как назвать команду Piped в Windows?

Question

Python - Подпроцесс - Как назвать команду Piped в Windows?

Используйте пакет listings .

Простая конфигурация для заголовка LaTeX (до \begin{document}):

\usepackage{listings}
\usepackage{color}

\definecolor{dkgreen}{rgb}{0,0.6,0}
\definecolor{gray}{rgb}{0.5,0.5,0.5}
\definecolor{mauve}{rgb}{0.58,0,0.82}

\lstset{frame=tb,
  language=Java,
  aboveskip=3mm,
  belowskip=3mm,
  showstringspaces=false,
  columns=flexible,
  basicstyle={\small\ttfamily},
  numbers=none,
  numberstyle=\tiny\color{gray},
  keywordstyle=\color{blue},
  commentstyle=\color{dkgreen},
  stringstyle=\color{mauve},
  breaklines=true,
  breakatwhitespace=true,
  tabsize=3
}

Вы можете изменить язык по умолчанию в середине документа с помощью \lstset{language=Java}.

Пример использования в документе:

\begin{lstlisting}
// Hello.java
import javax.swing.JApplet;
import java.awt.Graphics;

public class Hello extends JApplet {
    public void paintComponent(Graphics g) {
        g.drawString("Hello, world!", 65, 95);
    }    
}
\end{lstlisting}

Вот результат:

Example image

5

python subprocess pipe echo popen

задан Greg 25 June 2009 в 22:21

1 ответ

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python subprocess pipe echo popen

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score 11 · Accepted Answer

First and foremost, you don't actually need a pipe; you are just sending input. You can use subprocess.communicate for that.

Secondly, don't specify the command as a string; that's messy as soon as filenames with spaces are involved.

Thirdly, if you really wanted to execute a piped command, just call the shell. On Windows, I believe it's cmd /c program name arguments | further stuff.

Finally, single back slashes can be dangerous: "\p" is '\\p', but '\n' is a new line. Use os.path.join() or os.sep or, if specified outside python, just a forward slash.

proc = subprocess.Popen(
    ['C:/Program Files/GNU/GnuPG/gpg.exe',
    '--batch', '--passphrase-fd', '0',
    '--output ', 'c:/docume~1/usi/locals~1/temp/tmptlbxka.txt',
    '--decrypt', 'test.txt.gpg',],
    stdin=subprocess.PIPE,
    stdout=subprocess.PIPE,
   stderr=subprocess.STDOUT,
)
stdout_value, stderr_value = proc.communicate('bosco')