Как я заставляю urllib2 регистрировать ВСЕ переданные байты
Некоторые могут найти это полезным. Целочисленные значения в подстановке переменных, где трюк использует $(()) двойные скобки:
N=3
M=3
COUNT=$N-1
ARR[0]=3
ARR[1]=2
ARR[2]=4
ARR[3]=1
while (( COUNT < ${#ARR[@]} ))
do
ARR[$COUNT]=$((ARR[COUNT]*M))
(( COUNT=$COUNT+$N ))
done
2 ответа
Итак, я нашел, как настроить встроенный механизм отладки библиотеки:
import logging, urllib2, sys
hh = urllib2.HTTPHandler()
hsh = urllib2.HTTPSHandler()
hh.set_http_debuglevel(1)
hsh.set_http_debuglevel(1)
opener = urllib2.build_opener(hh, hsh)
logger = logging.getLogger()
logger.addHandler(logging.StreamHandler(sys.stdout))
logger.setLevel(logging.NOTSET)
Но я все еще ищу способ сбросить всю переданную информацию.
This looks pretty tricky to do. There are no hooks in urllib2, urllib, or httplib (which this builds on) for intercepting either input or output data.
The only thing that occurs to me, other than switching tactics to use an external tool (of which there are many, and most people use such things), would be to write a subclass of socket.socket in your own new module (say, "capture_socket") and then insert that into httplib using "import capture_socket; import httplib; httplib.socket = capture_socket". You'd have to copy all the necessary references (anything of the form "socket.foo" that is used in httplib) into your own module, but then you could override things like recv() and sendall() in your subclass to do what you like with the data.
Complications would likely arise if you were using SSL, and I'm not sure whether this would be sufficient or if you'd also have to make your own socket._fileobject as well. It appears doable though, and perusing the source in httplib.py and socket.py in the standard library would tell you more.