Мне также сказали, что [UIImage imageNamed:]
делает немного слишком много кэширования, и изображения не часто выпускаются. Мне сказали остерегаться использования его.
print_r
- ваш друг для выяснения структуры JSON.
<?php
$addresses = json_decode('{"addresses":{"address":[{"@array":"true","@id":"888888","@uri":"xyz","household":{"@id":"44444","@uri":"xyz"},"person":{"@id":"","@uri":""},"addressType":{"@id":"1","@uri":"xyz","name":"Primary"},"address1":"xyz","address2":null,"address3":null,"city":"xyz","postalCode":"111111"}]}}');
$_SESSION['address1'] = $addresses->addresses->address[0]->address1;
$_SESSION['address2'] = $addresses->addresses->address[0]->address2;
$_SESSION['address3'] = $addresses->addresses->address[0]->address3;
$_SESSION['city'] = $addresses->addresses->address[0]->city;
$_SESSION['postalCode'] = $addresses->addresses->address[0]->postalCode;
print_r($_SESSION);
Результаты в:
Array
(
[address1] => xyz
[address2] =>
[address3] =>
[city] => xyz
[postalCode] => 111111
)
json_decode декодирует строку в формате json в объект PHP .
Попробуйте следующее:
$results = json_decode($address);
$results['address1'] = $results->addresses->address[0]->address1;
$results['address2'] = $results->addresses->address[0]->address2;
$results['address3'] = $results->addresses->address[0]->address3;
$results['city'] = $results->addresses->address[0]->city;
$results['postalCode'] = $results->addresses->address[0]->postalCode;
Изменить - обновлено, сначала я неправильно прочитал ваш JSON.
Обратите внимание, что эти поля «@array» и «@id» являются недопустимой нотацией JSON, и технически они приводят к неопределенному поведению в парсерах JSON.
Почему бы не декодировать всю строку JSON, а затем получить то, что вам нужно?
$address = '{"addresses":{"address":[{"@array":"true","@id":"888888","@uri":"xyz","household":{"@id":"44444","@uri":"xyz"},"person":{"@id":"","@uri":""},"addressType":{"@id":"1","@uri":"xyz","name":"Primary"},"address1":"xyz","address2":null,"address3":null,"city":"xyz","postalCode":"111111"}]}}';
$results = json_decode($address, true);
$address = $results['addresses']['address'][0];
print $address['address1'];
print $address['address2'];
print $address['postalCode'];
вы можете использовать print_r для вывода результатов $, чтобы точно узнать, как выглядит вывод объекта.
Может быть, попробуйте $ results ['адреса'] ['адрес'] ['адрес1'];
Не знаю, почему вы используете strstr. но не похоже, что в данном случае это что-то изменит.
json_decode ($ jsonData) возвращает объект btw, а не массив.
Например:
stdClass Object
(
[addresses] => stdClass Object
(
[address] => Array
(
[0] => stdClass Object
(
[@array] => true
[@id] => 888888
[@uri] => xyz
[household] => stdClass Object
(
[@id] => 44444
[@uri] => xyz
)
[person] => stdClass Object
(
[@id] =>
[@uri] =>
)
[addressType] => stdClass Object
(
[@id] => 1
[@uri] => xyz
[name] => Primary
)
[address1] => xyz
[address2] =>
[address3] =>
[city] => xyz
[postalCode] => 111111
)
)
)
)
Способы доступа к данным:
$object = json_decode($jsonString);
$object->addresses->address[0]; // First address object
$object->addresses->address[0]->{"@array"}; // Not good way to access object property (damn @)
$object->addresses->address[0]->address1;
$object->addresses->address[0]->addressType->{"@id"}; // Again damn @
Если вы выполните print_r своего массива, вы увидите, как выглядит макет:
stdClass Object
(
[addresses] => stdClass Object
(
[address] => Array
(
[0] => stdClass Object
(
[@array] => true
[@id] => 888888
[@uri] => xyz
[household] => stdClass Object
(
[@id] => 44444
[@uri] => xyz
)
[person] => stdClass Object
(
[@id] =>
[@uri] =>
)
[addressType] => stdClass Object
(
[@id] => 1
[@uri] => xyz
[name] => Primary
)
[address1] => xyz
[address2] =>
[address3] =>
[city] => xyz
[postalCode] => 111111
)
)
)
)
Этот будет помещать все скалярные и нулевые значения в сеанс, где ключ не начинается с @
$jsonString = '{"addresses":{"address":[{"@array":"true","@id":"888888","@uri":"xyz","household":{"@id":"44444","@uri":"xyz"},"person":{"@id":"","@uri":""},"addressType":{"@id":"1","@uri":"xyz","name":"Primary"},"address1":"xyz","address2":null,"address3":null,"city":"xyz","postalCode":"111111"}]}}';
$result = json_decode($jsonString);
// will put *all* scalar and null values into session where key does not begin with a @
foreach($result->addresses->address[0] as $key=>$value) {
if (substr($key, 0, 1) != '@' && (is_scalar($value) || is_null($value)) ) {
$_SESSION[$key] = $value;
}
}
print_r($_SESSION);
?>