То, что лучший способ состоит в том, чтобы уменьшить ASP.NET, генерировало JavaScript?

Вот решение Scala. Я не доволен попыткой заставить его выглядеть коротким - я пожертвовал небольшим количеством удобочитаемости: (

object NumSpeller {
  val digits = Array("","one","two","three","four","five","six","seven","eight","nine")
  val teens = Array("ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen")
  val tens = Array("", "ten", "twenty", "thirty", "fourty", "fifty", "sixty", "seventy", "eighty", "ninety")
  val thousands = Array("", "thousand", "million", "billion", "trillion", "quadrillion", "quintillion")

  def spellGroup(num:Int) = {
    val (v3, v2, v1) = ((num / 100) % 10, (num / 10) % 10, num % 10)
    val hs = v3 match { case 0 => ""; case d => digits(d) + " hundred " }
    val ts = v2 match {
      case 0 => digits(v1)
      case 1 => teens(v1)
      case _ => v3 match { case 0 => tens(v2); case _ => tens(v2) + "-" + digits(v1) }
    }
    hs + ts
  }

  def numberGroups(num:Long) = {
    def _numberGroups(num:Long, factor:Int):List[(Double,Int)] = factor match {
      case 0 => List((num % 1000,0))
      case _ => ((num / Math.pow(1000, factor)) % 1000, factor) :: _numberGroups(num, factor - 1)
    }
    val ints = _numberGroups(num, 6) map (x => (x._1.asInstanceOf[Int],x._2))
    ints dropWhile (x => x._1 == 0.0)
  }

  def spell(num:Long) = num match { case 0 => "zero"; case _ => (numberGroups(num) map { x => spellGroup(x._1) + " " + thousands(x._2) + " " }).mkString.trim  }
}

Использование:

NumSpeller.spell(458582)