Поразрядно или: C# по сравнению с C++
Не делать.
Пираты будут пират. Неважно, что решение Вы придумываете, оно может и взламываться.
, С другой стороны, Ваши фактические, платящие клиенты - те, кому причиняет беспокойство дерьмо.
3 ответа
The & and | operators in C# are the same as in C/C++.
For instance, 2 | 8 is 10 and 2 & 8 is 0.
The difference is that an int is not automatically treated like a boolean value.
int and bool are distinct types in C#.
You need to compare an int to another int to get a bool.
if (2 & 8) ... // doesn't work
if ((2 & 8) != 0) ... // works
It's not the bitwise and/or operators that are different in C#. They work almost the same as in C++. The difference is that in C# there isn't an implicit conversion from integer to a boolean.
To fix your problem you just need to compare to zero:
if ((a | b) != 0) {
...
Unlike C/C++, C# maintains a pretty strict separation between arithmetic and boolean operations.
The designers of C# considered the automatic conversion of integral types to boolean to be a source of errors that they'd rather C# didn't have, so you have to explicitly make your arithmetic results to a boolean result by introducing a comparison:
if ((a | b) != 0) {
// ...
}
I think it's probably not a bad idea to do this in C/C++ as well, but I'll admit that I certainly don't strictly follow that advice (and I wouldn't argue for it very hard).