Удалите строку или столбец из 2D списка, если все значения (в той строке или столбце) не являются Ни одним

Также можно использовать встроенную функцию any(), которая проверяет, не имеет ли какой-либо элемент итерабеля значения None. Это быстрее, чем сравнение, и вам не нужно знать размер итерабела.

>>> def remove_rows( matrix ):
...    '''Returns a matrix without empty rows'''
...    ret_matrix = []
...    for row in matrix:
...        #Check if the row has any value or all are None
...        if any(row):
...            ret_matrix.append(row)
...
...    return ret_matrix
#You can do it also with a list comprehension, which will be even faster
>>> def remove_rows(matrix):
...     '''Returns a matrix without empty rows'''
...     ret_matrix = [ row for row in matrix if  any(row) ]
...     return ret_matrix

>>> grid = [
...         [{"some" : "thing"}, None, None, None, None],
...         [None, None, None, None, None],
...         [None, None, None, None, None],
...         [None, None, None, {"something" : "else"}, None],
...         [None, {"another" : "thing"}, None, None, None],
...         [None, None, None, None, None],
...         ]


>>> grid = remove_rows( grid )
>>> grid
[
 [{'some': 'thing'}, None, None, None, None], 
 [None, None, None, {'something': 'else'}, None], 
 [None, {'another': 'thing'}, None, None, None]
]

#transpose grid using zip (using asterisk)
>>> grid = zip(*grid)
#Note that zip returns tuples
>>> grid
[
  ({'some': 'thing'}, None, None), 
  (None, None, {'another': 'thing'}),
  (None, None, None), 
  (None, {'something': 'else'}, None), 
  (None, None, None)
]

>>> grid = remove_rows(grid)
>>> grid
[
  ({'some': 'thing'}, None, None), 
  (None, None, {'another': 'thing'}),
  (None, {'something': 'else'}, None)
]
>>> #Transpose again to get the first matrix, without empty rows or columns
>>> final_grid = zip(*grid)
>>> final_grid
[
 ({'some': 'thing'}, None, None),
 (None, None, {'something': 'else'}), 
 (None, {'another': 'thing'}, None)
]

Используйте zip() для транспонирования поврежденного массива, повторите процедуру очистки, затем zip() снова.

grid = ...

# remove empty rows
grid = [x for x in grid if any(x)]
# if any value you put in won't evaluate to False
# e.g. an empty string or empty list wouldn't work here
# in that case, use:
grid = [x for x in grid if any(n is not None for n in x)]

# remove empty columns
if not grid:
  raise ValueError("empty grid")
  # or whatever, as next line assumes grid[0] exists
empties = range(len(grid[0])) # assume all empty at first
for r in grid:
  empties = [c for c in empties if r[c] is None] # strip out non-empty
if empties:
  empties.reverse() # apply in reversed order
  for r in grid:
    for c in empties:
      r.pop(c)

Если бы у вас была функция транспонирования, вы могли бы сделать: transpose(removeRows(transpose(removeRows(mat))))

На самом деле ... использование битовой маски - лучшая идея.

Дайте мне подумать об этом ...

Сначала вычислите маску сетки:

grid_mask = [
10000,
00000,
00000,
00010,
00000
]

Теперь удалите нули:

grid_mask = [
10000,
00010,
]

Теперь и все значения по битам:

grid_mask = 10010

Теперь удалите все, кроме 1-го и 4-го столбцов.

Вот быстрая попытка

Это сработает для любой матрицы размеров, и строки тоже могут быть разного размера, и может быть быстрым :)

from collections import defaultdict
grid = [
        [{"some" : "thing"}, None, None, None, None],
        [None, None, None, None, None],
        [None, None, None, None, None],
        [None, None, None, {"something" : "else"}, None],
        [None, {"another" : "thing"}, None, None, None],
        [None, None, None, None, None],
        ]

# go thru the grid remove, rows which have all None
# doing that count None in each columns, remove such columns later
newGrid = []
colSize = len(grid)
colCount = defaultdict(int)
for row in grid:
    allNone = True
    for c, cell in enumerate(row):
        if cell is None:
            colCount[c] += 1
        else:
            allNone = False

    if not allNone: # only add rows which are not all none
        newGrid.append(row)

# get cols which need to be removed
removeCols = [col for col, count in colCount.iteritems() if count == colSize]
removeCols.sort(reverse=True) 

# now go thru each column and remove all None Columns
for row in newGrid:
    for col in removeCols:
        row.pop(col)

grid = newGrid
import pprint
pprint.pprint(grid)

вывод:

[[{'some': 'thing'}, None, None],
 [None, None, {'something': 'else'}],
 [None, {'another': 'thing'}, None]]