bash variable capture stderr and stdout separately or get exit value [duplicate]

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Capture stdout and stderr into different variables (13 answers)

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I need to capture the output and error of a command in my bash script and know whether the command succeeded or not.

At the moment, I am capturing both like this:

output=$(mycommand 2>&1)

I then need to check the exit value of mycommand. If it failed, I need to do some stuff with the output, if the command succeeded, I don't need to touch the output.

Since I am capturing the output, checking $? is always a 0 since bash succeeded at capturing the output into the variable.

This is a very time sensitive script, so we are trying to avoid any slower solutions like outputting to a file and re-reading it in.

If I could capture stdout to one variable and stderr to another, that would solve my problem because I could just check if the error variable was empty or not.

Thanks.

задан mhost 3 September 2010 в 02:18

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