Почему компилятор C # вставляет явную реализацию интерфейса?

I ran into a strange C# edge case and am looking for a good work-around.

There is a class that I do not control that looks like this:

namespace OtherCompany
{
    public class ClassIDoNotControl
    {
        public void SomeMethod(string argument)
        {
            Console.WriteLine((new StackFrame(1).GetMethod().Name));
        }
    }
}

I'd like to inherit from this class in a class I do control. Additionally, I'd like to specify an interface on it:

interface IInterfaceIDoControl
{
    void SomeMethod(string argument);
}

class ClassIDoControl : OtherCompany.ClassIDoNotControl, IInterfaceIDoControl
{
}

If all of these files are in the same assembly, everything works great:

namespace MyCompany
{
    class Program
    {
        static void Main(string[] args)
        {
            IInterfaceIDoControl i = new ClassIDoControl();
            i.SomeMethod("Hello World!"); // Prints "Main"
        }
    }
 }

But, if I move "ClassIDoNotControl" into another assembly, I don't get what I expected. Instead, I see "MyCompany.IInterfaceIDoControl.SomeMethod" for the output implying an extra stack frame.

The reason is that under the covers, the C# compiler is changing "ClassIDoControl" to look like this:

class ClassIDoControl : OtherCompany.ClassIDoNotControl, IInterfaceIDoControl
{
    void IInterfaceIDoControl.SomeMethod(string argument)
    {
        base.SomeMethod(argument);
    }
}

Is there a way to avoid this compiler-generated extra layer of indirection with explicitly implemented interfaces?