Why is T&& instantiated as int&?

Can anyone please explain why this compiles and why does t end up with type int&?

#include <utility>

void f(int& r)
{
    ++r;
}

template <typename Fun, typename T>
void g(Fun fun, T&& t) 
{ 
    fun(std::forward<T>(t)); 
}

int main()
{
    int i = 0;

    g(f, i);
}

I see this on GCC 4.5.0 20100604 and GDB 7.2-60.2