Virtual inheritance and static inheritance - mixing in C++

Если у вас что-то вроде этого:

#include <iostream>

template<typename T> class A
{
public:
    void func()
    {
        T::func();
    }
};

class B : public A<B>
{
public:
    virtual void func()
    {
        std::cout << "into func";
    }
};

class C : public B
{
};

int main()
{
  C c;
  c.func();

  return 0;
}

Вызывается ли func () динамически?
How could you implement class A such that if B has a virtual override, that it is dynamically dispatched, but statically dispatched if B doesn't?

Edit: My code didn't compile? Sorry guys. I'm kinda ill right now. My new code also doesn't compile, but that's part of the question. Also, this question is for me, not the faq.

#include <iostream>

template<typename T> class A
{
public:
    void func()
    {
        T::func();
    }
};

class B : public A<B>
{
public:
    virtual void func()
    {
        std::cout << "in B::func()\n";
    }
};

class C : public B
{
public:
    virtual void func() {
        std::cout << "in C::func()\n";
    }
};
class D : public A<D> {
    void func() {
        std::cout << "in D::func()\n";
    }
};
class E : public D {
    void func() {
        std::cout << "in E::func()\n";
    }
};

int main()
{
  C c;
  c.func();
  A<B>& ref = c;
  ref.func(); // Invokes dynamic lookup, as B declared itself virtual
  A<D>* ptr = new E;
  ptr->func(); // Calls D::func statically as D did not declare itself virtual
  std::cin.get();

  return 0;
}

visual studio 2010\projects\temp\temp\main.cpp(8): error C2352: 'B::func' : illegal call of non-static member function
      visual studio 2010\projects\temp\temp\main.cpp(15) : see declaration of 'B::func'
      visual studio 2010\projects\temp\temp\main.cpp(7) : while compiling class template member function 'void A<T>::func(void)'
      with
      [
          T=B
      ]
      visual studio 2010\projects\temp\temp\main.cpp(13) : see reference to class template instantiation 'A<T>' being compiled
      with
      [
          T=B
      ]