Плагин jQuery Form - как сделать ajaxForm () «живым»?

So I'm turning an "edit" form into an ajaxForm with the following:

$('#reviewForm').ajaxForm({
    success: function (response) {
        $('#bookReview').html(response);
    }
});

This returns the same form, that can be edited again, if necessary. The second form submission, however, no longer has the ajaxForm() attached to it, which makes sense.

How do I make sure this form is always an ajaxForm, no matter how many submissions have taken place, similar to how the live() function works?

8
задан asfsadf 26 September 2010 в 03:29
поделиться