Putting non-copyable objects into std-containers

Is this class design the standard C++0x way to prevent copy and assign, to protect client code against accidental double-deletion of data?

struct DataHolder {
  int *data;   // dangerous resource
  DataHolder(const char* fn); // load from file or so
  DataHolder(const char* fn, size_t len); // *from answers: added*
  ~DataHolder() { delete[] data; }

  // prevent copy, to prevent double-deletion
  DataHolder(const DataHolder&) = delete;
  DataHolder& operator=(const DataHolder&) = delete;

  // enable stealing
  DataHolder(DataHolder &&other) {
    data=other.data; other.data=nullptr;
  }
  DataHolder& operator=(DataHolder &&other) {
    if(&other!=this) { data = other.data; other.data=nullptr};
    return *this;
  }
};

You notice, that I defined the new move and move-assign methods here. Did I implement them correctly?

Is there any way I can -- with the move and move-assign definitions -- to put DataHolder in a standard container? like a vector? How would do I do that?

I wonder, some options come into mind:

// init-list. do they copy? or do they move?
// *from answers: compile-error, init-list is const, can nor move from there*
vector abc { DataHolder("a"), DataHolder("b"), DataHolder("c") };

// pushing temp-objects.
vector xyz;
xyz.push_back( DataHolder("x") );
// *from answers: emplace uses perfect argument forwarding*
xyz.emplace_back( "z", 1 );

// pushing a regular object, probably copies, right?
DataHolder y("y");
xyz.push_back( y ); // *from anwers: this copies, thus compile error.*

// pushing a regular object, explicit stealing?
xyz.push_back( move(y) );

// or is this what emplace is for?
xyz.emplace_back( y ); // *from answers: works, but nonsense here*

The emplace_back idea is just a guess, here.

Edit: I worked the answers into the example code, for readers convenience.