Lossless Join Decomposition

I am studying for a test, and this is on the study guide sheet. This is not homework, and will not be graded.

Relation Schema R = (A,B,C,D,E)

Functional Dependencies = (AB->E, C->AD, D->B, E->C)

Is r1 = (A,C,D) r2 = (B,C,E) OR

x1 = (A,C,D) x2 = (A,B,E) a lossless join decomposition? and why?

5
задан Mike 29 November 2010 в 04:33
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