Проверьте, существует ли значение в массиве массива

Регулярное выражение - наиболее эффективный способ решить эту проблему. Посмотрите на код ниже. Вдобавок, он также проверяет класс IP-адреса, в котором он принадлежит, и является ли он зарезервированным IP-адресом или нет

Pattern ipPattern;
int[] arr=new int[4];
int i=0;

//Method to check validity
 private String validateIpAddress(String ipAddress) {
      Matcher ipMatcher=ipPattern.matcher(ipAddress);

        //Condition to check input IP format
        if(ipMatcher.matches()) {       

           //Split input IP Address on basis of .
           String[] octate=ipAddress.split("[.]");     
           for(String x:octate) { 

              //Convert String number into integer
              arr[i]=Integer.parseInt(x);             
              i++;
         }

        //Check whether input is Class A IP Address or not
         if(arr[0]<=127) {                          
             if(arr[0]==0||arr[0]==127)
                 return(" is Reserved IP Address of Class A");
             else if(arr[1]==0&&arr[2]==0&&arr[3]==0)
                 return(" is Class A Network address");
             else if(arr[1]==255&&arr[2]==255&&arr[3]==255)
                 return( " is Class A Broadcast address");
             else 
                 return(" is valid IP Address of Class A");
         }

        //Check whether input is Class B IP Address or not
         else if(arr[0]>=128&&arr[0]<=191) {        
             if(arr[2]==0&&arr[3]==0)
                 return(" is Class B Network address");
             else if(arr[2]==255&&arr[3]==255)
                 return(" is Class B Broadcast address");
             else
                 return(" is valid IP Address of Class B");
         }

        //Check whether input is Class C IP Address or not
         else if(arr[0]>=192&&arr[0]<=223) {        
             if(arr[3]==0)
                 return(" is Class C Network address");
             else if(arr[3]==255)
                 return(" is Class C Broadcast address");
             else
                 return( " is valid IP Address of Class C");
        }

        //Check whether input is Class D IP Address or not
        else if(arr[0]>=224&&arr[0]<=239) {          
             return(" is Class D IP Address Reserved for multicasting");
        }

        //Execute if input is Class E IP Address
        else  {                                   
             return(" is Class E IP Address Reserved for Research and Development by DOD");
        }

    }

    //Input not matched with IP Address pattern
    else                                     
        return(" is Invalid IP Address");


}


public static void main(String[] args) {

    Scanner scan= new Scanner(System.in);
    System.out.println("Enter IP Address: ");

    //Input IP Address from user
    String ipAddress=scan.nextLine();  
    scan.close();
    IPAddress obj=new IPAddress();

    //Regex for IP Address
    obj.ipPattern=Pattern.compile("((([0-1]?\\d\\d?|2[0-4]\\d|25[0-5])\\.){3}([0-1]?\\d\\d?|2[0-4]\\d|25[0-5]))");

    //Display output
    System.out.println(ipAddress+ obj.validateIpAddress(ipAddress));

}
0
задан HashTag 13 July 2018 в 12:26
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