Сдвиньте весь столбец в многомерном массиве, используя только JavaScript или ES6
"""
Here is a simple python program showing how to use regular
expressions to write a paren-matching recursive parser.
This parser recognises items enclosed by parens, brackets,
braces and <> symbols, but is adaptable to any set of
open/close patterns. This is where the re package greatly
assists in parsing.
"""
import re
# The pattern below recognises a sequence consisting of:
# 1. Any characters not in the set of open/close strings.
# 2. One of the open/close strings.
# 3. The remainder of the string.
#
# There is no reason the opening pattern can't be the
# same as the closing pattern, so quoted strings can
# be included. However quotes are not ignored inside
# quotes. More logic is needed for that....
pat = re.compile("""
( .*? )
( \( | \) | \[ | \] | \{ | \} | \< | \> |
\' | \" | BEGIN | END | $ )
( .* )
""", re.X)
# The keys to the dictionary below are the opening strings,
# and the values are the corresponding closing strings.
# For example "(" is an opening string and ")" is its
# closing string.
matching = { "(" : ")",
"[" : "]",
"{" : "}",
"<" : ">",
'"' : '"',
"'" : "'",
"BEGIN" : "END" }
# The procedure below matches string s and returns a
# recursive list matching the nesting of the open/close
# patterns in s.
def matchnested(s, term=""):
lst = []
while True:
m = pat.match(s)
if m.group(1) != "":
lst.append(m.group(1))
if m.group(2) == term:
return lst, m.group(3)
if m.group(2) in matching:
item, s = matchnested(m.group(3), matching[m.group(2)])
lst.append(m.group(2))
lst.append(item)
lst.append(matching[m.group(2)])
else:
raise ValueError("After <<%s %s>> expected %s not %s" %
(lst, s, term, m.group(2)))
# Unit test.
if __name__ == "__main__":
for s in ("simple string",
""" "double quote" """,
""" 'single quote' """,
"one'two'three'four'five'six'seven",
"one(two(three(four)five)six)seven",
"one(two(three)four)five(six(seven)eight)nine",
"one(two)three[four]five{six}seven<eight>nine",
"one(two[three{four<five>six}seven]eight)nine",
"oneBEGINtwo(threeBEGINfourENDfive)sixENDseven",
"ERROR testing ((( mismatched ))] parens"):
print "\ninput", s
try:
lst, s = matchnested(s)
print "output", lst
except ValueError as e:
print str(e)
print "done"
-4
задан Keppy 19 February 2019 в 12:31
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2 ответа
Вы можете использовать array.map , чтобы переупорядочить значения:
function rearrange(rows, pos) {
return rows.map(function(cols) {
return pos.map(function(i) {
return cols[i];
});
});
}
var old_arr;
var new_arr;
old_arr = [
[1, 2, 3, 4],
[2, 2, 6, 4],
[4, 2, 3, 4],
[9, 2, 7, 4]
];
new_arr = rearrange(old_arr, [3, 0, 1, 2]);
console.log(new_arr);
old_arr = [
[1, 2, 3, 4],
[2, 2, 6, 4],
[4, 2, 3, 4],
[9, 2, 7, 4]
];
new_arr = rearrange(old_arr, [3, 2, 1, 0]);
console.log(new_arr);0
ответ дан Salman A 19 February 2019 в 12:31
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Вы можете добавить в отображаемый внешний массив новые элементы, разрезая внутренние массивы с заданным индексом.
Для получения оригинальной сортировки вы можете сдвинуть на дельту длины и индекса.
const shift = (array, index) => array.map(a => [...a.slice(index), ...a.slice(0, index)]);
var array = [[1, 2, 3, 4], [2, 2, 6, 4], [4, 2, 3, 4], [9, 2, 7, 4]],
index = 3;
array = shift(array, index);
console.log(array.map(a => a.join(' ')));
array = shift(array, array[0].length - index);
console.log(array.map(a => a.join(' ')));.as-console-wrapper { max-height: 100% !important; top: 0; }0
ответ дан Nina Scholz 19 February 2019 в 12:31
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