Я действительно посмотрел на множество идей, единственное решение было таким образом (работает с разными провайдерами электронной почты):
try
{
ViewProgressbar("Try to connect mail-server...", progressBar1.Value = 20);
string host = dsProvider.Rows[y]["POP_hostOut"].ToString();
int port = int.Parse(dsProvider.Rows[y]["POP_portOut"].ToString()); //587
string[] email = von1.Split('@');
string userName = (dsProvider.Rows[y]["login"].ToString() == "email[0]@email[1]")? email[0]+"@"+email[1] : email[0];
string password = layer.getUserPassword(listSender.SelectedValue.ToString());
SmtpClient client = new SmtpClient(host, port);
client.DeliveryMethod = SmtpDeliveryMethod.Network;
client.UseDefaultCredentials = false;
//A idea from MSDN but it not works. You got the "The server response was: 5.5.1 Authentication Required."
//System.Net.NetworkCredential myCreds = new System.Net.NetworkCredential(userName, password, host);
//System.Net.CredentialCache cache = new System.Net.CredentialCache();
//cache.Add(host, port, "NTLM", myCreds);
///cache.GetCredential(host, port, "NTLM"); //NTLM
client.Credentials = new System.Net.NetworkCredential(userName, password);
client.Host = host;
client.Port = port;
client.EnableSsl = true;
client.Send(message);
ViewProgressbar();
}
catch (SmtpException ex)...
Более общее решение, избегая жесткого кода и заполнения «NA» для отсутствующих данных:
my_dict = {('A1', 'A2'): 0.6, ('A3', 'A1'): 1, ('A2', 'A2'): 1, ('A2', 'A1'): 0.3}
labs = []
for key in my_dict.keys():
for k in key:
if k not in labs:
labs.append(k)
labs = sorted(labs)
print("Table\t" + "\t\t".join(labs))
for i in labs:
print(i, end="\t\t")
for j in labs:
try:
print(my_dict[(i, j)], end="\t\t")
except KeyError:
print("NA", end="\t\t")
print()
Table A1 A2 A3
A1 NA 0.6 NA
A2 0.3 1 NA
A3 1 NA NA
Вы можете использовать понимание списка:
my_dict = {('A1', 'A2'): 0.6, ('A1', 'A1'): 1, ('A2', 'A2'): 1, ('A2', 'A1'): 0.3}
table = [[[c for [d1, d2], c in my_dict.items() if f'A{i}' == d2 and f'A{b}' == d1][0]
for i in range(1, 3)] for b in range(1, 3)]
top = 'table {}'.format(' '.join(f'A{i}' for i in range(1, len(max(table, key=len))+1)))
final = '{}\n{}'.format(top, '\n'.join(f'A{i} {" ".join(map(str, a))}' for i, a in enumerate(table)))
Выход:
table A1 A2
A0 1 0.6
A1 0.3 1
print("Table A1 A2")
for i in ['A1','A2']:
print(i, end= " ")
for j in ['A1','A2']:
print(my_dict[(i,j)], end = " ")
print()
Выход
Table A1 A2
A1 1 0.6
A2 0.3 1