jQuery: this.attr () не функция?

    ArrayList<String> withDuplicates = new ArrayList<>();
    withDuplicates.add("1");
    withDuplicates.add("2");
    withDuplicates.add("1");
    withDuplicates.add("3");
    HashSet<String> set = new HashSet<>(withDuplicates);
    ArrayList<String> withoutDupicates = new ArrayList<>(set);

    ArrayList<String> duplicates = new ArrayList<String>();

    Iterator<String> dupIter = withDuplicates.iterator();
    while(dupIter.hasNext())
    {
    String dupWord = dupIter.next();
    if(withDuplicates.contains(dupWord))
    {
        duplicates.add(dupWord);
    }else{
        withoutDupicates.add(dupWord);
    }
    }
  System.out.println(duplicates);
  System.out.println(withoutDupicates);
23
задан informatik01 6 February 2018 в 14:39
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