Google Map Android Api V2 Пример кода не работает

Я немного исправил этот код: https://stackoverflow.com/a/1670085/5852630

Этот код работает с последовательной сортировкой: сначала выполните «OrderBy», затем «ThenBy» (не «OrderBy»!) [/ ​​g2]

public static IQueryable OrderBy(this IQueryable source, string orderByValues) where TEntity : class
{
    IQueryable returnValue = null;

    string[] orderPairs = orderByValues.Trim().Split(',');

    Expression resultExpression = source.Expression;

    string strAsc = "OrderBy";
    string strDesc = "OrderByDescending";

    foreach (string orderPair in orderPairs)
    {
        if (string.IsNullOrWhiteSpace(orderPair))
            continue;

        string[] orderPairArr = orderPair.Trim().Split(' ');

        string propertyName = orderPairArr[0].Trim();
        string orderNarrow = orderPairArr.Length > 1 ? orderPairArr[1].Trim() : string.Empty;

        string command = orderNarrow.ToUpper().Contains("DESC") ? strDesc : strAsc;

        Type type = typeof(TEntity);
        ParameterExpression parameter = Expression.Parameter(type, "p");

        System.Reflection.PropertyInfo property;
        Expression propertyAccess;

        if (propertyName.Contains('.'))
        {
            // support to be sorted on child fields. 
            String[] childProperties = propertyName.Split('.');
            property = typeof(TEntity).GetProperty(childProperties[0]);
            propertyAccess = Expression.MakeMemberAccess(parameter, property);

            for (int i = 1; i < childProperties.Length; i++)
            {
                Type t = property.PropertyType;
                if (!t.IsGenericType)
                {
                    property = t.GetProperty(childProperties[i]);
                }
                else
                {
                    property = t.GetGenericArguments().First().GetProperty(childProperties[i]);
                }

                propertyAccess = Expression.MakeMemberAccess(propertyAccess, property);
            }
        }
        else
        {
            property = type.GetProperty(propertyName);
            propertyAccess = Expression.MakeMemberAccess(parameter, property);
        }

        if (property.PropertyType == typeof(object))
        {
            propertyAccess = Expression.Call(propertyAccess, "ToString", null);
        }

        LambdaExpression orderByExpression = Expression.Lambda(propertyAccess, parameter);

        resultExpression = Expression.Call(typeof(Queryable), command, new Type[] { type, property.PropertyType == typeof(object) ? typeof(string) : property.PropertyType },
            resultExpression, Expression.Quote(orderByExpression));

        strAsc = "ThenBy";
        strDesc = "ThenByDescending";
    }

    returnValue = source.Provider.CreateQuery(resultExpression);

    return returnValue;
}

13
задан DarthCaniac 12 February 2014 в 18:13
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