Показ отчетов HTML в панели инструментов CruiseControl

Эта задача может выиграть от векторизации:

n = 500
AA = rand(n,1); % You used vectorization already (!) and not create each entry separately...
BB = AA>0.5;    % Results in a vector of logicals which signifies where the condition was met
SD = sum(BB)/n; % Can also be `nnz(BB)/n` or `mean(BB)`