Распаковка конструктора OCaml

Можно ли распаковать тип, привязав его данные к одному значению вместо кортежа?

# type foo = Foo of int * string;;
type foo = Foo of int * string
# Foo (3; "bar");;
  Foo (3; "bar");;
Error: The constructor Foo expects 2 argument(s),
       but is applied here to 1 argument(s)
# Foo (3, "bar");;
- : foo = Foo (3, "bar")

# (* Can this possibly work? *)
# let Foo data = Foo (3, "bar");;
  let Foo data = Foo (3, "bar");;
Error: The constructor Foo expects 2 argument(s),
       but is applied here to 1 argument(s)

# (* Here is the version that I know works: *)
# let Foo (d1, d2) = Foo (3, "bar");;
val d1 : int = 3
val d2 : string = "bar"

Возможно ли это синтаксически?