iPhone shortdate с 4 годами цифры
Shape может быть установлен на символ Unicode. Ниже приведены череп и скрещенные кости, но вы можете найти более подходящий символ.
Обратите внимание, что окончательный результат будет зависеть от шрифта, использованного для создания графика.
ggplot(data = df, aes(x =x, y=y)) +
geom_point(shape="\u2620", size = 10)
2 ответа
If you need four digit years, set the dateformat: using the exact format you'd like. The downside is you lose automatic locale formatting.
NSDateFormatter *dateFormatter = [[[NSDateFormatter alloc] init] autorelease];
[dateFormatter setDateFormat:@"MM/dd/yyyy"];
...
birthday.text = [dateFormatter stringFromDate:p.Birth];
If you need localization then you could try modifying the date format of the short style.
NSDateFormatter *dateFormatter = [[[NSDateFormatter alloc] init] autorelease ];
[dateFormatter setDateStyle:NSDateFormatterShortStyle];
[dateFormatter setTimeStyle:NSDateFormatterNoStyle];
if ([[dateFormatter dateFormat] rangeOfString:@"yyyy"].location == NSNotFound) {
NSString *fourDigitYearFormat = [[dateFormatter dateFormat] stringByReplacingOccurrencesOfString:@"yy" withString:@"yyyy"];
[dateFormatter setDateFormat:fourDigitYearFormat];
}
Updated with Bugfix from Max Macleod
kCFDateFormatterShortStyle Specifies a short style, typically numeric only, such as “11/23/37” or “3:30pm”.
Available in Mac OS X v10.3 and later.
Declared in CFDateFormatter.h.
NSDateFormatterShortStyle doesn't appear to give you 4 digit years.